line from transit setup A through piles 1, 2, 5, 10, 16,and 25. AB measures 50/sin 60°40´, or 57.35 feet. This,then, is the distance between adjacent transit setups onthe base line.The distance from the base line to the first offshorepile in any line also may be determined byright-triangle solution. For pile No. 1 this distance isprescribed as 50 feet. For piles 2, 3, and 4, first solvethe triangle A2L for 2L, which is 100/tan 29°20´, or177.95 feet. The distance from 2 to Q is 150 feet;therefore, QL measures 177.95 – 150, or 27.95 feet.QD amounts to 27.95/tan 60°40´, or 15.71 feet.Therefore, the distance from transit setup D to pile No.8 is 50 + 15.71, or 65.71 feet. Knowing the length ofQL and the distance from setup point B to pile No. 3by solving the right triangle LB3 for B3.You can determine the distance E9 by solving thedetermine the distance F15, G22, and H23 by solvingthe right triangle AN10 and proceeding as before. Forpile No. 24, the distance I24 amounts to 50 tan 29°20´,or 28.10 feet.OFFSHORE LOCATION BYTRIANGULATIONFor piles located farther offshore, thetriangulation method of location is preferred. A pilelocation diagram is shown in figure 10-30. It ispresumed that the piles in section X will be located bythe method just described, while those in section Y willbe located by triangulation from the two controlstations shown.The base line measures (1,038.83 – 433.27), or595.56 feet, from control station to control station.The middle line of piles runs from station 7 + 41.05,right triangle M5A and proceeding as before. You canmaking an angle of 84° with the base line. The pilesFigure 10-30.—File location diagram.10-28