6-43.What is the ratio of error ofclosure?1.1/9592.1/13203.1/45004.1/106006-44.What is the corrected latitude fora traverse line of 485.35 ft witha bearing of N 35°30’E?1.+394 .802.+395.133.+395.394.+395.46IN ANSWERING QUESTION 6-45, REFER TOFIGURE 7–15.6-45.Compute the departure of atraverse line 647.85 feet long,bearing N 15°45’W.1.-613.562.+613.563.-175.894.+175.896-46.What is meant by the terminversing?1.Computing the latitude anddeparture of a traverse linefrom its bearing and length2.Computing the bearing andlength of a traverse line fromits latitude and departure3.Computing the ratio of linearerror of closure of a traversefrom its length and error ofclosure4.Computing the latitude anddeparture from the correctedangles and distances6-47.Plane coordinates describe thelocation of a point in what manner?1.By a distance north or southand east or west from a pointof origin2.By bearing north or south andeast or west from a point oforigin3.By bearing and distance from apoint of origin4.By the line of sight from apoint of originLearning Objective: Computecoordinates from latitude anddeparture; compute latitude anddepartures from coordinates.IN ANSWERING QUESTIONS 6-48 THROUGH 6-50,ASSUME THAT A TRAVERSE LINE HAS THEFOLLOWING PLANE COORDINATESSTATION A X = 627.42 Y = 326.87STATION B X = 864.81 Y = 542.506-48.What is the latitude of thetraverse line?1.-215.63 ft2.+215.63 ft3.-237.39 ft4.+237.39 ft6-49.What is the departure of thetraverse line?1.-215.63 ft2.+215.63 ft3.-237.39 ft4.+237.39 ft6-50.What is the bearing of the traverseline?1.N47°45’E2.N42°15’E3.S47°45’W4.S42°15’W39
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