9-20.The dimensions for computations ofarea by resolution are obtained inwhat manner?1.By scale of the plot2.By field measurements3.Both 1 and 2 above4.By interpolationFigure 9AIN ANSWERING QUESTIONS 9-21 THROUGH 9-29,REFER TO THE FIELD NOTES SHOWN IN FIGURE9A. THE ROAD IS 30 FEET WIDE WITH 2:1FILL SLOPES. (IN THE NOTES, CUT IS PLUSAND FILL IS MINUS.)IN ANSWERING QUESTIONS 9-21 THROUGH 9-24,COMPUTE THE CROSS-SECTIONAL AREA ATSTATION 2 + 00 BY USING THE FOLLOWINGFORMULA:9-21.What is the value of dr?1.17.4 ft2.24.8 ft3.27.2 ft4.29.0 ft9-22.What is the value of c?1.-6.1 ft2.-5.6 ft3.-4.9 ft4.-6.1 ft9-23.What is the value of h1?1.1.2 ft2.4.1 ft3.4.9 ft4.5.6 ft9-24.What is the area of the crosssection?1.166.8 ft2.228.1 ft3.373.7 ft4.475.6 ftIN ANSWERING QUESTIONS 9-25 THROUGH 9-28,USE THE COORDINATES METHOD TO DETERMINETHE CROSS-SECTIONAL AREA AT STATION3 + 00. THREE OF THE NEEDED COORDINATESARE SHOWN IN THE NOTES; YOU WILL NEEDTHREE MORE COORDINATES. ONE OF THESE ISTHE POINT OF ORIGIN THAT WILL BE ATCENTER-LINE FINISHED GRADE (COORDINATES0/0).THE OTHER TWO COORDINATES ARE THETHREE ROAD EDGES TO THE LEFT AND TO THERIGHT.9-25.9-26.9-27.9-28.What is the coordinate of the leftedge of the road?1.0/152.0/-153.1.2/17.44.7.0/29.0When you write down the coordinatesbeginning at the right edge of theroad and go clockwise around thecross section, your firstmultiplication would be1.-7[29 - 15]2.-7[0 - 15]3.-7[4.1 - 0]4.-7[-17.4 - (-15)]Continuing with the above pro-cedure, the last computationwould be1.-4.1[29 - 14.4]2.-4.1[-15 - 17.4]3.-1.2[-15-0]4.-1.2[-17.4 - (-15)]What is the area of the crosssection?1.67.3 sq ft2.85.3 sq ft3.156.6 sq ft4.313.2 sq ft61
Integrated Publishing, Inc. - A (SDVOSB) Service Disabled Veteran Owned Small Business