9-20.
The dimensions for computations of
area by resolution are obtained in
what manner?
1.
By scale of the plot
2.
By field measurements
3.
Both 1 and 2 above
4.
By interpolation
Figure 9A
IN ANSWERING QUESTIONS 9-21 THROUGH 9-29,
REFER TO THE FIELD NOTES SHOWN IN FIGURE
9A. THE ROAD IS 30 FEET WIDE WITH 2:1
FILL SLOPES. (IN THE NOTES, CUT IS PLUS
AND FILL IS MINUS.)
IN ANSWERING QUESTIONS 9-21 THROUGH 9-24,
COMPUTE THE CROSS-SECTIONAL AREA AT
STATION 2 + 00 BY USING THE FOLLOWING
FORMULA:
9-21.
What is the value of dr?
1.
17.4 ft
2.
24.8 ft
3.
27.2 ft
4.
29.0 ft
9-22.
What is the value of c?
1.
-6.1 ft
2.
-5.6 ft
3.
-4.9 ft
4.
-6.1 ft
9-23.
What is the value of h1?
1.
1.2 ft
2.
4.1 ft
3.
4.9 ft
4.
5.6 ft
9-24.
What is the area of the cross
section?
1.
166.8 ft
2.
228.1 ft
3.
373.7 ft
4.
475.6 ft
IN ANSWERING QUESTIONS 9-25 THROUGH 9-28,
USE THE COORDINATES METHOD TO DETERMINE
THE CROSS-SECTIONAL AREA AT STATION
3 + 00. THREE OF THE NEEDED COORDINATES
ARE SHOWN IN THE NOTES; YOU WILL NEED
THREE MORE COORDINATES. ONE OF THESE IS
THE POINT OF ORIGIN THAT WILL BE AT
CENTER-LINE FINISHED GRADE (COORDINATES
0/0).
THE OTHER TWO COORDINATES ARE THE
THREE ROAD EDGES TO THE LEFT AND TO THE
RIGHT.
9-25.
9-26.
9-27.
9-28.
What is the coordinate of the left
edge of the road?
1.
0/15
2.
0/-15
3.
1.2/17.4
4.
7.0/29.0
When you write down the coordinates
beginning at the right edge of the
road and go clockwise around the
cross section, your first
multiplication would be
1.
-7[29 - 15]
2.
-7[0 - 15]
3.
-7[4.1 - 0]
4.
-7[-17.4 - (-15)]
Continuing with the above pro-
cedure, the last computation
would be
1.
-4.1[29 - 14.4]
2.
-4.1[-15 - 17.4]
3.
-1.2[-15-0]
4.
-1.2[-17.4 - (-15)]
What is the area of the cross
section?
1.
67.3 sq ft
2.
85.3 sq ft
3.
156.6 sq ft
4.
313.2 sq ft
61