10-36.
This bisects the interior angle
at the point of intersection:
1. A
2. B
3. C
4. D
10-37.
For a degree of curvature of 1°,
the radius is 5,729.58 ft. Which
of the following equations could
be used to derive this value?
1.
2.
3.
4.
Each of the above
Learnning Objective: Recognize
correct procedures and perform
mathematical computations to solve
simple horizontal curve
situations.
10-38.
To solve for the tangent distance,
you must know what information?
1.
2.
3.
4.
Point of tangency
Point of curvature
Central angle and radius
Each of the above
10-39.
You must know the degree of the
curve to solve for which of the
following information?
1.
Chord distance
2.
Curve distance
3.
Tangent distance
4.
External distance
10-40.
When calculating the length of the
curve using the chord definition,
you obtain a value sightly less
than the true length of the curve.
1.
True
2.
False
10-41.
What is the recommended procedure
for laying out a curve?
1.
Swing the arc with a tape
2.
Set up a transit at the PI
and turn the interior angles
3.
Set up a transit at the PC
and turn the interior angles
4.
Set up the transit at the PC
and turn deflection angles
10-42.
The degree of curve required for
the layout of a road section is
20°. When you lay out this curve,
what chord length should you use
to minimize the difference between
arc and chord distances?
1.
10 ft
2.
25 ft
3.
50 ft
4.
100 ft
IN ANSWERING QUESTIONS 10-43 THROUGH
10-52, YOU ARE TO LAY OUT A HORIZONTAL
CURVE BY ARC DEFINITION, USING THE
FOLLOWING DATA:
PI = Sta. 16 + 24.60
I = 60°
D = 8°
10-43.
HOW long is the radius(R) for the
curve?
1.
708.20 ft
2.
716.20 ft
3.
720.20 ft
4.
728.20 ft
10-44.
What is the plus station at the
PC?
1.
12 + 11.10
2.
12 + 12.60
3.
20 + 38.10
4.
20 + 40.20
10-45.
What station should you mark
the stake at the PT?
1.
23 + 74.60
2.
23 + 46.10
3.
19 + 61.10
4.
19 + 51.10
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